(一) 实现登录功能
- 需求说明
(1) . 输入注册时的用户名和密码，登录成功，提示欢迎信息
(2) . 如果用户名和密码输入错误，提示用户继续输入，最多有3次输入机会
int max = 99999;
int min = 1000;
Random rd = new Random();
rd.Next(min, max);
int a = 0;
string user = "";
string key = "";
string b = "";
Console.WriteLine("*****欢迎进入奖客富翁系统*****");
Console.WriteLine(" 1.注册");
Console.WriteLine(" 2.登录");
Console.WriteLine(" 3.抽奖");
Console.WriteLine("******************************");
Console.WriteLine("请选择菜单：");
a = Convert.ToInt32(Console.ReadLine());
switch (a)
{
case 1:
Console.WriteLine("[奖客富翁系统>注册]");
Console.WriteLine("请填写用户注册信息:");
Console.WriteLine("用户名:");
user = Console.ReadLine();
Console.WriteLine("密码:");
key = Console.ReadLine();
Console.WriteLine("注册成功，请记好你的会员卡号");
Console.WriteLine("用户名\t\t密码\t\t会员卡号");
Console.WriteLine("{0}\t\t{1}\t\t{2}", user, key, rd.Next(min, max));
Console.WriteLine("继续吗?(y/n)");
b = Console.ReadLine();
break;
case 2:
Console.WriteLine("[奖客富翁系统>登录]");
user = "admin";
key = "123456";
int i = 2;
while (i > -1)
{
Console.WriteLine("请输入用户名:");
string yonghu = Console.ReadLine();
Console.WriteLine("请输入密码:");
string mima = Console.ReadLine();
if (user == yonghu & key == mima & i > 0)
{
Console.WriteLine("欢迎您:{0}", yonghu);
break;
}
else
{
if (i > -1)
{
Console.WriteLine("你还剩{0}次机会", i);
i--;
continue;
}
else
{
Console.WriteLine("你的机会用完了");
break;
}
}
}
break;
case 3:
Console.WriteLine("[奖客富翁系统>抽奖]");
break;
}
Console.WriteLine("继续吗？（y/n）");
b = Console.ReadLine(); switch (b)
{
case "n":
Console.WriteLine("系统退出，谢谢使用");
break;
case "y":
Console.WriteLine("");
break;
}
Console.ReadKey();
