# Question

Given an unsorted array return whether an increasing subsequence of length 3 exists or not in the array.
Formally the function should:

Return true if there exists *i, j, k *
such that arr[i] < arr[j] < arr[k] given 0 ≤ i < j < kn-1 else return false.

Your algorithm should run in O(n) time complexity and O(1) space complexity.
Examples:
Given [1, 2, 3, 4, 5],
return true.
Given [5, 4, 3, 2, 1],
return false.

# Code

public class Solution {
public boolean increasingTriplet(int[] nums) {
// if (nums == null || nums.length < 3) return false;

// int[] dp = new int[nums.length];
// dp[0] = 1;

// for (int i = 1; i < dp.length; i++) {
//     dp[i] = 1;
//     for (int j = 0; j < i; j++) {
//         if (nums[j] < nums[i]) {
//             dp[i] = Math.max(dp[i], dp[j] + 1);
//         }
//         if (dp[i] == 3) return true;
//     }
// }

// return false;
int min = Integer.MAX_VALUE, secondMin = Integer.MAX_VALUE;

for (int n: nums) {
if (n <= min) {
min = n;
} else if (n <= secondMin) {
secondMin = n;
} else return true;
}

return false;
}
}