题目：http://www.lydsy.com/JudgeOnline/problem.php?id=1026
裸的数位统计，不过还是很恶心额。。不使劲对拍的话死活A不了555
代码：
#include <cstdio>
#include <algorithm>
#include <cstring>
using namespace std ;
#define rep( i , x ) for ( ll i = 0 ; i < x ; ++ i )
#define maxn 20
typedef long long ll ;
ll f[ maxn ][ 10 ] , pre[ maxn ][ 10 ] , cnt , ans ;
ll N[ maxn ] , a , b ;
void dfs( ll now ) {
if ( ! now ) {
rep( i , N[ now ] + 1 ) pre[ now ][ i ] = 1 ;
return ;
}
rep( i , N[ now ] ) {
rep( j , 10 ) if ( abs( i - j ) >= 2 ) {
pre[ now ][ i ] += f[ now - 1 ][ j ] ;
}
}
dfs( now - 1 ) ;
rep( i , 10 ) if ( abs( N[ now ] - i ) >= 2 ) {
pre[ now ][ N[ now ] ] += pre[ now - 1 ][ i ] ;
}
}
void cal( ll x ) {
if ( ! x ) {
cnt = 0 ;
return ;
}
ll len = 0 ;
for ( ; x ; x /= 10 ) N[ len ++ ] = x % 10 ;
if ( len == 1 ) {
cnt = N[ 0 ] + 1 ; return ;
}
memset( f , 0 , sizeof( f ) ) ;
rep( i , len ) {
if ( ! i ) {
rep( j , 10 ) f[ i ][ j ] = 1 ;
} else {
rep( j , 10 ) rep( k , 10 ) if ( abs( j - k ) >= 2 ) {
f[ i ][ j ] += f[ i - 1 ][ k ] ;
}
}
}
memset( pre , 0 , sizeof( pre ) ) ;
dfs( len - 1 ) ;
cnt = 0 ;
rep( i , 10 ) if ( i ) cnt += pre[ len - 1 ][ i ] ;
rep( i , len - 1 ) rep( j , 9 ) cnt += f[ i ][ j + 1 ] ;
}
int main( ) {
scanf( "%lld%lld" , &a , &b ) ;
cal( b ) ;
ans = cnt ;
cal( a - 1 ) ;
printf( "%lld\n" , ans - cnt ) ;
return 0 ;
}
