# 鹅毛诗人、红学家、作家唐国明哥德巴赫猜想1＋1创新的最全证明公式

Geese poet, red scientist, writer Tang Guoming Goddebach conjecture 1 + 1 innovation of the most complete proof formula:

The "1 + 1" general formula is:

(Even number> 2; said prime number of digits in front of the number of prime number of its number of digits can only take the range of 1,2,3,5,7,9 cycle to take; n> 0)

Geese poet, red scientist, writer Tang Guoming Goddebach conjecture 1 + 1 innovation of the most complete proof formula principle:

A number of even no matter how many of its single digits are fled 0,2,4,6,8; a no matter how many prime, its single digits in addition to 2 and 5 of the two prime, its single digits (Note, this sentence can also be expressed as: no matter how much prime, its single digits can only be 1,2,3,5,7,9 - for the Special prime numbers 2 and 5, since even-numbered 4 can only be expressed by the sum of prime numbers 2 plus 2, and the prime number 5 is summed with any prime number, and the sum is always a single digit of 0, 2, 4, .) Regardless of the infinity of even infinity, it can be expressed as the sum of the two prime numbers. Because an even number is expressed as the sum of two primes, it is only necessary to add the number of digits of the two prime numbers to satisfy the even-numbered bits 0, 2, 4, 6, 8 unconditionally. So even greater than 2 or not less than 4 even can be expressed as the sum of the two prime number is absolutely established. Concise that is, because the prime number 2 and 5 into more than 10 single digits can only be a co-number, 4 can only be even the number of 2 plus 2 sum; so no matter how much prime, its single digits Always 1, 2, 3, 5, 7, 9, no matter how big even, its single digits are always 0,2,4,6,8, so even more than 2 even can be the sum of two prime numbers.

——每个不小于6的偶数都可以是两个奇素数之和

（或任何一个大于2的偶数，都可以是两个素数之和）

Tang Guoming uses the "single digit" method to prove the most complete proof of Goldbach's conjecture 1 + 1 innovation（唐国明用“个位数”法对哥德巴赫猜想11创新的最全证明

- each even less than 6 even can be the sum of two odd prime numbers（——每个不小于6的偶数都可以是两个奇素数之和）

(Or any one greater than 2 even, can be the sum of two prime numbers)（（或任何一个大于2的偶数，都可以是两个素数之和））

Address: No. 28, Xiangyangpo, Hunan Normal University, Yuelu District, Changsha, Hunan Province,China

Telephone (micro signal): 13467607858

QQ number: 63300905

E-mail: 63300905@qq.com

Author: Tang Guoming

Tang Guoming, male, Han nationality, now living in Changsha, Hunan Province Writers Association, since the published works, has been in the "poetry" "Zhongshan" "Beijing literature" "Star" poetry and other domestic and foreign publications published hundreds of works Words. Published in 2016 in the United States and the Peruvian "International Daily" published in the Chinese version of the series, to read the way to read the archaeological excavation buried in the high after the 40 back in the Cao Xueqin pen, archaeological science to repair the resurrection in line with Cao Xueqin rhyme and Cao Xueqin Creation of the original "red school" works "Dream of Red Mansions after eight back Cao Wen archaeological restoration: 81 to 100 back". Zhejiang TV, Liaoning TV, Liaoning TV, Hubei TV and other television stations, "New Weekly" "China Daily", "Chinese Culture News", "Guangzhou Daily", "Xiaoxiang Morning News" "Sanxiang Metropolis Daily "" Changsha Evening News "" Xi'an Evening News "and other newspapers reported.

Abstract: Mathematical circles are accustomed to the "1 + 1" proposition with the words "each of the even numbers greater than or equal to 6 can be the sum of two odd prime numbers." Since prime numbers 2 and 5 become more than 10 single digits, The sum of four, can only be even the number of 2 plus 2 and, so Goldbach conjecture "1 +1" the original proposition is "any one greater than 2 even, can be two prime sum."

The "1 + 1" general formula is:

(Even number> 2; said prime number of digits in front of the number of prime number of its number of digits can only take the range of 1,2,3,5,7,9 cycle to take; n> 0)

“1＋1”成立的理论过程

1234321＝1111×1111＝（101×11）×（101×11）

15455711041＝124321×124321＝ [（101×11）×（101×11）] ×[（101×11）×（101×11）]

15455711041也是不能被2、3、5、7整除的合数。再如素数13乘以19的积是247，247也不能被2、3、5、7整除，247乘以247的积61009也不能被2、3、5、7整除。61009乘以61009的乘积3722098081也是个不能被2、3、5、7整除的合数，如果把61009乘以任意一个素数13的乘积793117照样不能被2、3、5、7整除，再把61009乘以任意一个素数17所得的乘积1037153也是一个不能被2、3、5、7整除的合数，其他例证无须再举，从而可知：

47，37，59； 53，43，61，41，31；

1＋3＋5﹦9；1＋3＋7﹦11；1＋3＋9﹦13；

3＋3＋9﹦15；1＋7＋9﹦17；

1＋3＋7＋9﹦20；1＋1＋3＋7﹦12；1＋3＋3＋7﹦14；

1＋3＋5＋7﹦16；9＋9＋9＋1﹦28；（其他省略）

5×9＝45；3×3×9＝81；1×3×7×9＝189；

3×3×3×3×7＝567；（其他省略）

“1＋n”与“s ＋ z”成立的论证过程

“1＋1”成立的公式证明过程

[1] 陈景润 《初级数论Ⅰ》哈尔滨工业大学出版社 2012-05-01

[2]《世界三大数学猜想》《哥德巴赫猜想（世界近代三大数学难题之一）》《素数》《奇数》《偶数》《素因数》《因数》百度百科 2017

2017年3月30日—2017年6月9日写于岳麓山下