题目
Given a group of two strings, you need to find the longest uncommon subsequence of this group of two strings. The longest uncommon subsequence is defined as the longest subsequence of one of these strings and this subsequence should not be any subsequence of the other strings.
A subsequence is a sequence that can be derived from one sequence by deleting some characters without changing the order of the remaining elements. Trivially, any string is a subsequence of itself and an empty string is a subsequence of any string.
The input will be two strings, and the output needs to be the length of the longest uncommon subsequence. If the longest uncommon subsequence doesn't exist, return -1.
Example 1:
Input: "aba", "cdc"
Output: 3
Explanation: The longest uncommon subsequence is "aba" (or "cdc"),
because "aba" is a subsequence of "aba",
but not a subsequence of any other strings in the group of two strings.
Note:
- Both strings' lengths will not exceed 100.
- Only letters from a ~ z will appear in input strings.
难度
Easy
方法
这题太简单，不要考虑复杂了。如果字符串a,b不相等，那么它们最长的不相同的子字符串长度就是max(len(a), len(b))，如果a==b，则返回-1
python代码
class Solution(object):
def findLUSlength(self, a, b):
"""
:type a: str
:type b: str
:rtype: int
"""
if a==b:
return -1
return max(len(a), len(b))
assert Solution().findLUSlength("aba", "cbc") == 3
